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Fix for the procedure signature to have an parent object and the parameters share the same parent value.

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This commit is contained in:
Henrique Gottardi Werlang 2025-03-20 17:58:43 -03:00
parent 74fbb1f24f
commit a8d97d35e0
1 changed files with 5 additions and 5 deletions
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10
packages/rtl/src/rtti.pas
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@ -243,7 +243,7 @@ type
procedure LoadFlags;
procedure LoadParameters;
public
constructor Create(const Signature: TProcedureSignature);
constructor Create(const Parent: TRttiObject; const Signature: TProcedureSignature);
class function Invoke(const Instance: TValue; const Args: array of TValue): TValue;
@ -2227,7 +2227,7 @@ end;
function TRttiMethod.GetProcedureSignature: TRttiProcedureSignature;
begin
if not Assigned(FProcedureSignature) then
FProcedureSignature := TRttiProcedureSignature.Create(MethodTypeInfo.ProcSig);
FProcedureSignature := TRttiProcedureSignature.Create(Self, MethodTypeInfo.ProcSig);
Result := FProcedureSignature;
end;
@ -2872,9 +2872,9 @@ end;
{ TRttiProcedureSignature }
constructor TRttiProcedureSignature.Create(const Signature: TProcedureSignature);
constructor TRttiProcedureSignature.Create(const Parent: TRttiObject; const Signature: TProcedureSignature);
begin
inherited Create(nil, Signature);
inherited Create(Parent, Signature);
FReturnType := Pool.GetType(Signature.ResultType);
@ -2927,7 +2927,7 @@ begin
for A := Low(FParameters) to High(FParameters) do
begin
Param := MethodParams[A];
RttiParam := TRttiParameter.Create(Self, Param);
RttiParam := TRttiParameter.Create(Parent, Param);
RttiParam.FName := Param.Name;
RttiParam.FParamType := Pool.GetType(Param.TypeInfo);